Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Ils | 2972 | 142 | 1 | 142.0000 |
Mais | 4204 | 106 | 1 | 106.0000 |
Ces | 3318 | 252 | 3 | 84.0000 |
Il | 15613 | 371 | 7 | 53.0000 |
Cela | 1783 | 92 | 2 | 46.0000 |
Comme | 952 | 44 | 1 | 44.0000 |
Plusieurs | 377 | 39 | 1 | 39.0000 |
Cette | 5662 | 349 | 10 | 34.9000 |
Des | 2444 | 236 | 7 | 33.7143 |
pouvez | 1659 | 93 | 3 | 31.0000 |
Certains | 477 | 30 | 1 | 30.0000 |
Sa | 587 | 60 | 2 | 30.0000 |
Alors | 817 | 28 | 1 | 28.0000 |
devons | 1020 | 79 | 3 | 26.3333 |
Car | 451 | 25 | 1 | 25.0000 |
C’est | 3376 | 92 | 4 | 23.0000 |
Cet | 1159 | 68 | 3 | 22.6667 |
close | 851 | 44 | 2 | 22.0000 |
Les | 21380 | 1194 | 56 | 21.3214 |
avons | 2875 | 168 | 8 | 21.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
visant | 720 | 2 | 46 | 0.0435 |
capables | 218 | 1 | 13 | 0.0769 |
feuille | 212 | 1 | 13 | 0.0769 |
relatives | 499 | 3 | 36 | 0.0833 |
Calques | 165 | 2 | 22 | 0.0909 |
liés | 643 | 4 | 44 | 0.0909 |
essayer | 111 | 1 | 10 | 0.1000 |
remarquer | 85 | 1 | 10 | 0.1000 |
quant | 753 | 3 | 30 | 0.1000 |
Image | 370 | 2 | 19 | 0.1053 |
horaire | 66 | 1 | 9 | 0.1111 |
d'au | 111 | 1 | 9 | 0.1111 |
essayé | 83 | 1 | 9 | 0.1111 |
mises | 584 | 3 | 26 | 0.1154 |
l’ensemble | 1012 | 3 | 25 | 0.1200 |
Land | 108 | 1 | 8 | 0.1250 |
couverts | 109 | 1 | 8 | 0.1250 |
lors | 3236 | 18 | 144 | 0.1250 |
géré | 95 | 1 | 8 | 0.1250 |
entrer | 265 | 3 | 24 | 0.1250 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II